查看: 1696|回复: 0

C语言算法经典87-94

[复制链接]
  • TA的每日心情
    开心
    2018-2-7 14:55
  • 签到天数: 51 天

    连续签到: 1 天

    [LV.5]常住居民I

    发表于 2017-10-12 10:14:02 | 显示全部楼层 |阅读模式
    分享到:
    【程序87
    题目:回答结果(结构体变量传递)
    1.程序分析:
    2.程序源代码:
    #include "stdio.h"
    struct student
    { int x;
    char c;
    } a;
    main()
    {a.x=3;
    a.c='a';
    f(a);
    printf("%d,%c",a.x,a.c);
    }
    f(struct student b)
    {
    b.x=20;
    b.c='y';
    }
    ==============================================================
    【程序88嵌入式信盈达企鹅要妖气呜呜吧久零纪要
    题目:读取7个数(1—50)的整数值,每读取一个值,程序打印出该值个数的*。
    1.程序分析:
    2.程序源代码:
    main()
    {int i,a,n=1;
    while(n<=7)
    { do {
    scanf("%d",&a);
    }while(a<1||a>50);
    for(i=1;i<=a;i++)
    printf("*");
    printf("\n");
    n++;}
    getch();
    }
    ==============================================================
    【程序89
    题目:某个公司采用公用电话传递数据,数据是四位的整数,在传递过程中是加密的,加密规则如下:
    每位数字都加上5,然后用和除以10的余数代替该数字,再将第一位和第四位交换,第二位和第三位交换。
    1.程序分析:
    2.程序源代码:
    main()
    {int a,i,aa[4],t;
    scanf("%d",&a);
    aa[0]=a ;
    aa[1]=a 0/10;
    aa[2]=a 00/100;
    aa[3]=a/1000;
    for(i=0;i<=3;i++)
    {aa+=5;
    aa%=10;
    }
    for(i=0;i<=3/2;i++)
    {t=aa;
    aa=aa[3-i];
    aa[3-i]=t;
    }
    for(i=3;i>=0;i--)
    printf("%d",aa);
    }
    ==============================================================
    【程序90
    题目:专升本一题,读结果。
    1.程序分析:
    2.程序源代码:
    #include "stdio.h"
    #define M 5
    main()
    {int a[M]={1,2,3,4,5};
    int i,j,t;
    i=0;j=M-1;
    while(i {t=*(a+i);
    *(a+i)=*(a+j);
    *(a+j)=t;
    i++;j--;
    }
    for(i=0;i printf("%d",*(a+i));
    }
    【程序91
    题目:时间函数举例1
    1.程序分析:
    2.程序源代码:
    #include "stdio.h"
    #include "time.h"
    void main()
    { time_t lt; /*define a longint time varible*/
    lt=time(NULL);/*system time and date*/
    printf(ctime(<)); /*english format output*/
    printf(asctime(localtime(<)));/*tranfer to tm*/
    printf(asctime(gmtime(<))); /*tranfer to Greenwich time*/
    }
    ==============================================================
    【程序92
    题目:时间函数举例2
    1.程序分析:
    2.程序源代码:
    /*calculate time*/
    #include "time.h"
    #include "stdio.h"
    main()
    { time_t start,end;
    int i;
    start=time(NULL);
    for(i=0;i<3000;i++)
    { printf("\1\1\1\1\1\1\1\1\1\1\n");}
    end=time(NULL);
    printf("\1: The different is %6.3f\n",difftime(end,start));
    }
    ==============================================================
    【程序93
    题目:时间函数举例3
    1.程序分析:
    2.程序源代码:
    /*calculate time*/
    #include "time.h"
    #include "stdio.h"
    main()
    { clock_t start,end;
    int i;
    double var;
    start=clock();
    for(i=0;i<10000;i++)
    { printf("\1\1\1\1\1\1\1\1\1\1\n");}
    end=clock();
    printf("\1: The different is %6.3f\n",(double)(end-start));
    }
    ==============================================================
    【程序94
    题目:时间函数举例4,一个猜数游戏,判断一个人反应快慢。(版主初学时编的)
    1.程序分析:
    2.程序源代码:
    #include "time.h"
    #include "stdlib.h"
    #include "stdio.h"
    main()
    {char c;
    clock_t start,end;
    time_t a,b;
    double var;
    int i,guess;
    srand(time(NULL));
    printf("do you want to play it.('y' or 'n') \n");
    loop:
    while((c=getchar())=='y')
    {
    i=rand() 0;
    printf("\nplease input number you guess:\n");
    start=clock();
    a=time(NULL);
    scanf("%d",&guess);
    while(guess!=i)
    {if(guess>i)
    {printf("please input a little smaller.\n");
    scanf("%d",&guess);}
    else
    {printf("please input a little bigger.\n");
    scanf("%d",&guess);}
    }
    end=clock();
    b=time(NULL);
    printf("\1: It took you %6.3f seconds\n",var=(double)(end-start)/18.2);
    printf("\1: it took you %6.3f seconds\n\n",difftime(b,a));
    if(var<15)
    printf("\1\1 You are very clever! \1\1\n\n");
    else if(var<25)
    printf("\1\1 you are normal! \1\1\n\n");
    else
    printf("\1\1 you are stupid! \1\1\n\n");
    printf("\1\1 Congradulations \1\1\n\n");
    printf("The number you guess is %d",i);
    }
    printf("\ndo you want to try it again?(\"yy\".or.\"n\")\n");
    if((c=getch())=='y')
    goto loop;
    }

    回复

    使用道具 举报

    您需要登录后才可以回帖 注册/登录

    本版积分规则

    关闭

    站长推荐上一条 /2 下一条



    手机版|小黑屋|与非网

    GMT+8, 2024-4-19 22:24 , Processed in 0.106713 second(s), 15 queries , MemCache On.

    ICP经营许可证 苏B2-20140176  苏ICP备14012660号-2   苏州灵动帧格网络科技有限公司 版权所有.

    苏公网安备 32059002001037号

    Powered by Discuz! X3.4

    Copyright © 2001-2020, Tencent Cloud.